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World Science Scholars
20.7 Coordinates for Time
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Coordinates for Time—Problem 1

A train moving at a velocity v=0.5cv = 0.5c goes through a tunnel. From the perspective of the tunnel, the Lorentz contracted length of the train equals the length of the tunnel itself. For the tunnel’s frame of reference we use coordinates (t,x)(t,x). Assume that the front of the train enters the tunnel at (t=0,x=0)(t = 0,x = 0). Moreover, assume that the length of the tunnel and the Lorentz contracted length of the train are both 300 feet.

  1. 1. Question

    What are the (t,x)(t,x) coordinates of the front of the train leaving the tunnel?

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  2. 2. Question

    What are the (t,x)(t,x) coordinates of the back of the train entering the tunnel?

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  3. 3. Question

    What are the (t,x)(t,x) coordinates of the back of the train leaving the tunnel?

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