World Science Scholars
5.1 The Mathematics of Speed
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Sajith Perumbilavil
If we also consider a case, where V and W are both C, then (V+W)/(1+VW/C^2) gives a value C. But if the two beams are moving in the same direction, then: (V-W)/(1-VW/C^2) gives the undefined value (0/0). How do we interpret this?
Cristino Pérez Ramos
He was not looking!! Haha
Samyak Sanghvi
V=W THEN IT BECOMES (V-V)/(1-(V/C)^2)=0 (as v/c is not equal to 1 for them to cancel out the denominator)
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